didppy.CBFS
- class didppy.CBFS(model, f_operator=0, primal_bound=None, time_limit=None, get_all_solutions=False, quiet=False, initial_registry_capacity=1000000)
Cyclic Best-First Search (CBFS) solver.
This performs CBFS using the dual bound as the heuristic function.
To apply this solver, the cost must be computed in the form of
x + state_cost,x * state_cost,didppy.max(x, state_cost), ordidppy.min(x, state_cost)where,state_costis either ofIntExpr.state_cost()andFloatExpr.state_cost(), andxis a value independent ofstate_cost. Otherwise, it cannot compute the cost correctly and may not produce the optimal solution.- Parameters:
model (Model) – DyPDL model to solve.
f_operator (FOperator, default: FOperator.Plus) – Operator to combine a g-value and the dual bound to compute the f-value. If the cost is computed by
+, this should bePlus. If the cost is computed by*, this should beProduct. If the cost is computed bymax, this should beMax. If the cost is computed bymin, this should beMin.primal_bound (int, float, or None, default: None) – Primal bound.
time_limit (int, float, or None, default: None) – Time limit.
get_all_solutions (bool, default: False) – Return a solution if it is not improving when
search_next()is called.quiet (bool, default: False) – Suppress the log output or not.
initial_registry_capacity (int, default: 1000000) – Initial size of the data structure storing all generated states.
- Raises:
TypeError – If the type of
primal_boundand the cost type ofmodelare different.OverflowError – If
initial_registry_capacityis negative.PanicException – If
time_limitis negative.
References
Ryo Kuroiwa and J. Christopher Beck. “Solving Domain-Independent Dynamic Programming with Anytime Heuristic Search,” Proceedings of the 33rd International Conference on Automated Planning and Scheduling (ICAPS), 2023.
Gio K. Kao, Edward C. Sewell, and Sheldom H. Jacobson. “A Branch, Bound and Remember Algorithm for the 1|r_i|Σt_i scheduling problem,” Journal of Scheduling, vol. 12(2), pp. 163-175, 2009.
Examples
Example with
+operator.>>> import didppy as dp >>> model = dp.Model() >>> x = model.add_int_var(target=1) >>> model.add_base_case([x == 0]) >>> t = dp.Transition( ... name="decrement", ... cost=1 + dp.IntExpr.state_cost(), ... effects=[(x, x - 1)] ... ) >>> model.add_transition(t) >>> model.add_dual_bound(x) >>> solver = dp.CBFS(model, quiet=True) >>> solution = solver.search() >>> print(solution.cost) 1
Example with
maxoperator.>>> import didppy as dp >>> model = dp.Model() >>> x = model.add_int_var(target=2) >>> model.add_base_case([x == 0]) >>> t = dp.Transition( ... name="decrement", ... cost=dp.max(x, dp.IntExpr.state_cost()), ... effects=[(x, x - 1)] ... ) >>> model.add_transition(t) >>> model.add_dual_bound(x) >>> solver = dp.CBFS(model, f_operator=dp.FOperator.Max, quiet=True) >>> solution = solver.search() >>> print(solution.cost) 2
Methods
search()Search for the optimal solution of a DyPDL model.
Search for the next solution of a DyPDL model.
- search()
Search for the optimal solution of a DyPDL model.
- Returns:
Solution.
- Return type:
- Raises:
PanicException – If the model is invalid.
Examples
>>> import didppy as dp >>> model = dp.Model() >>> x = model.add_int_var(target=1) >>> model.add_base_case([x == 0]) >>> t = dp.Transition( ... name="decrement", ... cost=1 + dp.IntExpr.state_cost(), ... effects=[(x, x - 1)] ... ) >>> model.add_transition(t) >>> model.add_dual_bound(x) >>> solver = dp.CBFS(model, quiet=True) >>> solution = solver.search() >>> solution.cost 1
- search_next()
Search for the next solution of a DyPDL model.
- Returns:
solution (Solution) – Solution.
terminated (bool) – Whether the search is terminated.
- Raises:
PanicException – If the model is invalid.
Examples
>>> import didppy as dp >>> model = dp.Model() >>> x = model.add_int_var(target=1) >>> model.add_base_case([x == 0]) >>> t = dp.Transition( ... name="decrement", ... cost=1 + dp.IntExpr.state_cost(), ... effects=[(x, x - 1)] ... ) >>> model.add_transition(t) >>> model.add_dual_bound(x) >>> solver = dp.CBFS(model, quiet=True) >>> solution, terminated = solver.search_next() >>> solution.cost 1 >>> terminated True